Let us assume that we have a certain function y = f (x), which is strictly monotonic (decreasing or increasing) and continuous on the domain of definition x ∈ a; b ; its range of values y ∈ c ; d, and on the interval c; d in this case we will have a function defined x = g (y) with a range of values a ; b. The second function will also be continuous and strictly monotonic. With respect to y = f (x) it will be an inverse function. That is, we can talk about the inverse function x = g (y) when y = f (x) will either decrease or increase over a given interval.
These two functions, f and g, will be mutually inverse.
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Why do we even need the concept of inverse functions?
We need this to solve the equations y = f (x), which are written precisely using these expressions.
Let's say we need to find a solution to the equation cos (x) = 1 3 . Its solutions will be two points: x = ± a r c o c s 1 3 + 2 π · k, k ∈ Z
For example, the inverse cosine and cosine functions will be inverse to each other.
Let's look at several problems to find functions that are inverse to given ones.
Example 1
Condition: what is the inverse function for y = 3 x + 2?
Solution
The domain of definitions and range of values of the function specified in the condition is the set of all real numbers. Let's try to solve this equation through x, that is, by expressing x through y.
We get x = 1 3 y - 2 3 . This is the inverse function we need, but y will be the argument here, and x will be the function. Let's rearrange them to get a more familiar notation:
Answer: the function y = 1 3 x - 2 3 will be the inverse of y = 3 x + 2.
Both mutually inverse functions can be displayed on a graph as follows:
We see the symmetry of both graphs regarding y = x. This line is the bisector of the first and third quadrants. We have obtained a proof of one of the properties of mutually inverse functions, which we will discuss later.
Let's take an example in which we need to find the logarithmic function that is the inverse of a given exponential function.
Example 2
Condition: determine which function will be the inverse for y = 2 x.
Solution
For a given function, the domain of definition is all real numbers. The range of values lies in the interval 0; + ∞ . Now we need to express x in terms of y, that is, solve the specified equation in terms of x. We get x = log 2 y. Let's rearrange the variables and get y = log 2 x.
As a result, we have obtained exponential and logarithmic functions, which will be mutually inverse to each other throughout the entire domain of definition.
Answer: y = log 2 x .
On the graph, both functions will look like this:
Basic properties of mutually inverse functions
In this paragraph we list the main properties of the functions y = f (x) and x = g (y), which are mutually inverse.
Definition 1
- We already derived the first property earlier: y = f (g (y)) and x = g (f (x)).
- The second property follows from the first: the domain of definition y = f (x) will coincide with the range of values of the inverse function x = g (y), and vice versa.
- The graphs of functions that are inverse will be symmetrical with respect to y = x.
- If y = f (x) is increasing, then x = g (y) will increase, and if y = f (x) is decreasing, then x = g (y) will also decrease.
We advise you to pay close attention to the concepts of domain of definition and domain of meaning of functions and never confuse them. Let's assume that we have two mutually inverse functions y = f (x) = a x and x = g (y) = log a y. According to the first property, y = f (g (y)) = a log a y. This equality will be true only if positive values y , and for negative logarithms the logarithm is not defined, so don’t rush to write down that a log a y = y . Be sure to check and add that this is only true when y is positive.
But the equality x = f (g (x)) = log a a x = x will be true for any real values of x.
Don't forget about this point, especially if you have to work with trigonometric and inverse trigonometric functions. So, a r c sin sin 7 π 3 ≠ 7 π 3, because the arcsine range is π 2; π 2 and 7 π 3 are not included in it. The correct entry will be
a r c sin sin 7 π 3 = a r c sin sin 2 π + π 3 = = a r c sin sin π 3 = π 3
But sin a r c sin 1 3 = 1 3 is a correct equality, i.e. sin (a r c sin x) = x for x ∈ - 1 ; 1 and a r c sin (sin x) = x for x ∈ - π 2 ; π 2. Always be careful with the range and scope of inverse functions!
- Basic mutually inverse functions: power functions
If we have a power function y = x a , then for x > 0 the power function x = y 1 a will also be its inverse. Let's replace the letters and get, respectively, y = x a and x = y 1 a.
On the graph they will look like this (cases with positive and negative coefficient a):
- Basic mutually inverse functions: exponential and logarithmic
Let's take a, which will be a positive number not equal to 1.
Graphs for functions with a > 1 and a< 1 будут выглядеть так:
- Basic mutually inverse functions: trigonometric and inverse trigonometric
If we were to plot the main branch sine and arcsine, it would look like this (shown as the highlighted light area).
Transcript
1 Mutually inverse functions Two functions f and g are called mutually inverse if the formulas y=f(x) and x=g(y) express the same relationship between the variables x and y, i.e. if the equality y=f(x) is true if and only if the equality x=g(y) is true: y=f(x) x=g(y) If two functions f and g are mutually inverse, then g is called the inverse function for f and, conversely, f is the inverse function for g. For example, y=10 x and x=lgy are mutually inverse functions. Condition for the existence of a mutually inverse function A function f has an inverse if, from the relation y=f(x), the variable x can be uniquely expressed through y. There are functions for which it is impossible to unambiguously express the argument through the given value of the function. For example: 1. y= x. For a given positive number y, there are two values of the argument x such that x = y. For example, if y=2, then x=2 or x= - 2. This means that it is impossible to express x unambiguously through y. Therefore, this function does not have a reciprocal. 2. y=x 2. x=, x= - 3. y=sinx. For a given value of y (y 1), there are infinitely many values of x such that y=sinx. The function y=f(x) has an inverse if every straight line y=y 0 intersects the graph of the function y=f(x) at no more than one point (it may not intersect the graph at all if y 0 does not belong to the range of values of the function f) . This condition can be formulated differently: the equation f(x)=y 0 for each y 0 has at most one solution. The condition that a function has an inverse is certainly satisfied if the function is strictly increasing or strictly decreasing. If f is strictly increasing, then for two different values of the argument it takes different meanings, since a larger argument value corresponds to a larger function value. Consequently, the equation f(x)=y for a strictly monotone function has at most one solution. Exponential function y=a x is strictly monotonic, so it has an inverse logarithmic function. Many functions do not have inverses. If for some b the equation f(x)=b has more than one solution, then the function y=f(x) does not have an inverse. On a graph, this means that the line y=b intersects the graph of the function at more than one point. For example, y=x 2 ; y=sinx; y=tgx.
2 The ambiguity of the solution to the equation f(x) = b can be dealt with by reducing the domain of definition of the function f so that its range of values does not change, but so that it takes each value once. For example, y=x 2, x 0; y=sinx, ; y=tgx,. General rule finding the inverse function for a function: 1. solving the equation for x, we find; 2. Changing the designations of the variable x to y, and y to x, we obtain the inverse function of the given one. Properties of mutually inverse functions Identities Let f and g be mutually inverse functions. This means that the equalities y=f(x) and x=g(y) are equivalent: f(g(y))=y and g(f(x))=x. For example, 1. Let f be an exponential function and g a logarithmic function. We get: i. 2. The functions y=x2, x0 and y= are mutually inverse. We have two identities: and for x 0. Domain of definition Let f and g be mutually inverse functions. The domain of the function f coincides with the domain of the function g, and, conversely, the domain of the function f coincides with the domain of the function g. Example. The domain of definition of the exponential function is the entire numerical axis R, and its range of values is the set of all positive numbers. For a logarithmic function it is the opposite: the domain of definition is the set of all positive numbers, and the range of values is the entire set of R. Monotonicity If one of the mutually inverse functions is strictly increasing, then the other is strictly increasing. Proof. Let x 1 and x 2 be two numbers lying in the domain of definition of the function g, and x 1 3 Graphs of mutually inverse functions Theorem. Let f and g be mutually inverse functions. The graphs of the functions y=f(x) and x=g(y) are symmetrical to each other with respect to the bisector of the angle how. Proof. By the definition of mutually inverse functions, the formulas y=f(x) and x=g(y) express the same dependence between the variables x and y, which means that this dependence is depicted by the same graph of some curve C. Curve C is a graph functions y=f(x). Let's take an arbitrary point P(a; b) C. This means that b=f(a) and at the same time a=g(b). Let us construct a point Q symmetrical to the point P relative to the bisector of the angle xy. Point Q will have coordinates (b; a). Since a=g(b), then point Q belongs to the graph of the function y=g(x): indeed, for x=b, the value of y=a is equal to g(x). Thus, all points symmetrical to the points of the curve C relative to the indicated straight line lie on the graph of the function y=g(x). Examples of functions whose graphs are mutually inverse: y=e x and y=lnx; y=x 2 (x 0) and y= ; y=2x 4 and y= +2. 4 Derivative of an inverse function Let f and g be mutually inverse functions. The graphs of the functions y=f(x) and x=g(y) are symmetrical to each other with respect to the bisector of the angle how. Let's take the point x=a and calculate the value of one of the functions at this point: f(a)=b. Then, by definition of the inverse function, g(b)=a. The points (a; f(a))=(a; b) and (b; g(b))=(b; a) are symmetrical about the straight line l. Since the curves are symmetrical, the tangents to them are symmetrical with respect to the straight line l. From symmetry, the angle of one of the lines with the x-axis is equal to the angle of the other line with the y-axis. If a straight line forms an angle α with the x-axis, then its angular coefficient is equal to k 1 =tgα; then the second straight line has an angular coefficient k 2 =tg(α)=ctgα=. Thus, the angular coefficients of lines symmetrical with respect to straight line l are mutually inverse, i.e. k 2 =, or k 1 k 2 =1. Moving on to derivatives and taking into account that the slope of the tangent is the value of the derivative at the point of contact, we conclude: The values of the derivatives of mutually inverse functions at the corresponding points are mutually inverse, i.e. Example 1. Prove that the function f(x) = x 3, reversible. Solution. y=f(x)=x 3. The inverse function will be the function y=g(x)=. Let's find the derivative of the function g:. Those. =. Task 1. Prove that the function given by the formula is invertible 1) 2) 3) 4) 5) 6) 7) 8) 9) 10) 5 Example 2. Find the inverse function of the function y=2x+1. Solution. The function y=2x+1 is increasing, therefore it has an inverse. Let's express x through y: we get.. Moving on to generally accepted notations, Answer: Task 2. Find inverse functions for these functions 1) 2) 3) 4) 5) 6) 7) 8) 9) 10) Chapter 9 Degrees Degree with an integer exponent. 0 = 0; 0 = ; 0 = 0. > 0 > 0 ; > >.. >. If it's even, then ()< (). Например, () 0 = 0 < 0 = = () 0. Если нечетно, то () >(). For example, () = > = = (), so What we will study: Lesson on the topic: Study of a function for monotonicity. Decreasing and increasing functions. Relationship between derivative and monotonicity of a function. Two important theorems about monotonicity. Examples. Guys, we 6 Problems leading to the concept of derivative Let a material point move in a straight line in one direction according to the law s f (t), where t is time and s is path, traversable by point during time t Let us note a certain moment 1 SA Lavrenchenko Lecture 12 Inverse functions 1 The concept of an inverse function Definition 11 A function is called one-to-one if it does not take any value more than once, those of which follow when Lecture 5 Derivatives of basic elementary functions Abstract: Physical and geometric interpretations of the derivative of a function of one variable are given. Examples of differentiation of functions and rules are considered. Chapter 1. Limits and continuity 1. Number sets 1 0. Real numbers From school mathematics you know natural N integers Z rational Q and real R numbers Natural and integer numbers Numerical functions and numerical sequences D. V. Lytkina NPP, I semester D. V. Lytkina (SibGUTI) mathematical analysis of NPP, I semester 1 / 35 Contents 1 Numerical function Concept of function Numerical functions. Lecture 19 DERIVATIVE AND ITS APPLICATIONS. DEFINITION OF DERIVATIVE. Let us have some function y=f(x), defined on some interval. For each value of the argument x from this interval, the function y=f(x) Chapter 5 Study of functions using the Taylor formula Local extremum of a function Definition Function = f (reaches a local maximum (minimum) at point c, if it is possible to specify a δ > such that its increment Department of Mathematics and Computer Science Elements of Higher Mathematics Educational and methodological complex for secondary vocational education students studying using distance technologies Module Differential calculus Compiled by: Department of Mathematics and Computer Science Mathematical analysis Educational and methodological complex for higher education students studying using distance technologies Module 4 Derivative applications Compiled by: Associate Professor Tasks for independent solution. Find the domain of the function 6x. Find the tangent of the angle of inclination to the x-axis of the tangent passing through point M (;) of the graph of the function. Find the tangent of the angle Topic Theory of Limits Practical lesson Number sequences Definition of a number sequence Bounded and unbounded sequences Monotonic sequences Infinitesimal 44 Example Find the total derivative complex function= sin v cos w where v = ln + 1 w= 1 Using formula (9) d v w v w = v w d sin cos + cos cos + 1 sin sin 1 Now find the total differential of the complex function f MODULE “Application of continuity and derivative. Application of the derivative to the study of functions." Application of continuity.. Interval method.. Tangent to the graph. Lagrange's formula. 4. Application of derivative Moscow Institute of Physics and Technology Exponential, logarithmic equations and inequalities, method of potentiation and logarithm in solving problems. Methodical manual in preparation for the Olympics. Chapter 8 Functions and graphs Variables and dependencies between them. Two quantities are called directly proportional if their ratio is constant, that is, if =, where is a constant number that does not change with changes Ministry of Education of the Republic of Belarus EDUCATIONAL INSTITUTION "GRODNO STATE UNIVERSITY NAMED AFTER YANKA KUPALA" Yu.Yu. Gnezdovsky, V.N. Gorbuzov, P.F. Pronevich EXPONENTARIAL AND LOGARITHMIC Topic Numerical function, its properties and graph Concept of a numerical function Domain of definition and set of values of a function Let a numerical set X be given A rule that associates each number X with a unique I Definition of a function of several variables Domain of definition When studying many phenomena, one has to deal with functions of two or more independent variables. For example, body temperature in at the moment 1. Definite integral 1.1. Let f be a bounded function defined on the segment [, b] R. A partition of the segment [, b] is a set of points τ = (x, x 1,..., x n 1, x n) [, b] such that = x< x 1 < < x n 1 Lecture Study of a function and construction of its graph Abstract: The function is studied for monotonicity, extremum, convexity-concavity, the existence of asymptotes An example of the study of a function is given, construction Subject. Function. Methods of assignment. Implicit function. Inverse function. Classification of functions Elements of set theory. Basic concepts One of the basic concepts of modern mathematics is the concept of set. Topic 2.1 Numerical functions. Function, its properties and graph Let X and Y Some number sets If each, according to some rule F, is assigned a single element, then they say that Given Algebra and beginnings of analysis, XI ALGEBRA AND BEGINNINGS OF ANALYSIS According to the Regulations on the state (final) certification of graduates of XI (XII) classes educational institutions Russian Federation students take L.A. Strauss, I.V. Barinova Problems with a parameter in the Unified State Examination Methodological recommendations y=-x 0 -a- -a x -5 Ulyanovsk 05 Strauss L.A. Problems with a parameter in the Unified State Exam [Text]: methodological recommendations/ L.A. Strauss, I.V. Chapter 3. Study of functions using derivatives 3.1. Extrema and monotonicity Consider the function y = f (), defined on a certain interval I R. They say that it has a local maximum at the point Subject. Logarithmic equations, inequalities and systems of equations I. General instructions 1. While working on the topic, analyzing examples and independently solving the proposed problems, try in each case What we will study: Lesson on the topic: Finding extrema points of functions. 1) Introduction. 2) Minimum and maximum points. 3) Extremum of the function. 4) How to calculate extrema? 5) Examples Guys, let's see 1 SA Lavrenchenko Lecture 13 Exponential and logarithmic functions 1 The concept of an exponential function Definition 11 An exponential function is a function of the form base is a positive constant, where Function Webinar 5 Topic: Repetition Preparing for the Unified State Exam (task 8) Task 8 Find all values of the parameter a, for each of which the equation a a 0 has either seven or eight solutions Let, then t t Original equation Moscow State Technical University named after N.E. Bauman Faculty of Fundamental Sciences Department of Mathematical Modeling A.N. Kaviakovykov, A.P. Kremenko General information Problems with parameters Equations with module tasks type tasks C 5 1 Preparation for the Unified State Exam Dikhtyar M.B. 1. Absolute value, or the modulus of a number x, is the number x itself if x 0; number x, I. V. Yakovlev Materials on mathematics MathUs.ru Logarithm In this article we give the definition of a logarithm, derive basic logarithmic formulas, give examples of calculations with logarithms, and also consider 13. Partial derivatives of higher orders Let = have and are defined on D O. The functions and are also called first-order partial derivatives of a function or first partial derivatives of a function. and in general Ministry of Education and Science of the Russian Federation Federal State Budgetary educational institution higher education"NIZHNY NOVGOROD STATE TECHNICAL UNIVERSITY IM R E CONTENTS ALGEBRA AND BEGINNINGS OF FUNCTION ANALYSIS...10 Basic properties of functions...11 Even and odd...11 Periodicity...12 Zeros of a function...12 Monotonicity (increasing, decreasing)...13 Extrema (maxima INTRODUCTION TO MATHEMATICAL ANALYSIS Lecture. The concept of set. Definition of function basic properties. Basic elementary functions CONTENTS: Elements of set theory The set of real numbers Numerical Topic 36 “Properties of Functions” We will analyze the properties of a function using the example of the graph of an arbitrary function y = f(x): 1. The domain of definition of a function is the set of all values of the variable x that have the corresponding Asymptotes Graph of a function Cartesian coordinate system Linear fractional function Quadratic trinomial Linear function Local extremum Set of values of a quadratic trinomial Set of values of a function Ural Federal University, Institute of Mathematics and Computer Science, Department of Algebra and Discrete Mathematics Introductory remarks This lecture is devoted to the study of the plane. The material presented in it DIFFERENTIAL EQUATIONS 1. Basic concepts A differential equation for a certain function is an equation that connects this function with its independent variables and its derivatives. MATHEMATICS Unified State Exam Assignments C5 7 Inequalities (domain method) Directions and solutions Reference material Sources Koryanov A G Bryansk Send comments and suggestions to: korynov@milru PROBLEMS WITH PARAMETERS Topic 41 “Tasks with a parameter” Basic formulations of tasks with a parameter: 1) Find all values of the parameter, for each of which a certain condition is satisfied.) Solve an equation or inequality with Topic 39. “Derivatives of functions” Function The derivative of a function at the point x 0 is the limit of the ratio of the increment of a function to the increment of a variable, that is, = lim = lim + () Table of derivatives: Derivative Department of Mathematics and Computer Science Elements of Higher Mathematics Educational and methodological complex for secondary vocational education students studying using distance technologies Module Theory of Limits Compiled by: Associate Professor Derivative of a function Its geometric and physical meaning Differentiation technique Basic definitions Let f () be defined on (,) a, b some fixed point, the increment of the argument at the point, Differentiation of an implicitly given function Consider the function (,) = C (C = const) This equation defines the implicit function () Suppose we solved this equation and found the explicit expression = () Now we can Ministry of Education and Science of the Russian Federation Yaroslavsky state university named after PG Demidova Department of Discrete Analysis COLLECTION OF PROBLEMS FOR INDEPENDENT SOLUTION ON THE TOPIC LIMIT OF FUNCTION Regional scientific and practical conference of educational, research and design work students in grades 6-11 “Applied and fundamental issues of mathematics” Methodological aspects of studying mathematics Use Limits and continuity. Limit of a function Let the function = f) be defined in some neighborhood of the point = a. Moreover, at point a itself the function is not necessarily defined. Definition. The number b is called the limit Unified state exam in mathematics, year 7 demo version Part A Find the value of the expression 6p p with p = Solution We use the property of degrees: Substitute into the resulting expression Correct 0.5 Logarithmic equations and inequalities. Used literature:. Algebra and principles of analysis 0 - edited by A.N. Kolmogorov. Independent and tests in algebra 0 - edited by E.P. Ershov System of problems on the topic “Tangent Equation” Determine the sign slope tangent drawn to the graph of the function y f (), at points with abscissas a, b, c a) b) Indicate the points at which the derivative Inequalities with a parameter on the unified state exam VV Silvestrov The tasks of the unified state exam (USE) certainly contain problems with parameters Examination work plan 008 Algebraic equations where Definition. An equation of the form 0, P () 0, some real numbers is called algebraic. 0 0 At the same time variable quantity is called the unknown, and the numbers 0, coefficients Equations of a line and a plane Equation of a line on a plane.. General equation of a line. A sign of parallelism and perpendicularity of lines. In Cartesian coordinates, each straight line on the Oxy plane is defined Graph of the derivative of a function Intervals of monotonicity of a function Example 1. The figure shows a graph of y =f (x) of the derivative of the function f (x), defined on the interval (1;13). Find the intervals of increasing function Samples basic tasks and questions on MA for the semester Limit of the sequence Simplest Calculate the limit of the sequence l i m 2 n 6 n 2 + 9 n 6 4 n 6 n 4 6 4 n 6 2 2 Calculate the limit of the sequence Problems in analytical geometry, Mechanics and Mathematics, Moscow State University Problem Given a tetrahedron O Express in terms of vectors O O O the vector EF with the beginning in the middle E of the edge O and the end at the point F of the intersection of the medians of the triangle Solution Let Problem statement Half division method Chord method (method of proportional parts 4 Newton method (tangent method 5 Iteration method (successive approximation method) Problem statement Let given 1. Expressions and transformations 1.1 Root of degree n The concept of a root of degree n Properties of a root of degree n: Root of a product and product of roots: simplify the expression; find the values of the root of the quotient LECTURE N4. Differential of a function of the first and higher orders. Invariance of the shape of the differential. Derivatives of higher orders. Application of differential in approximate calculations. 1.The concept of differential.... MODULE 7 “Exponential and logarithmic functions.” Generalization of the concept of degree. Root of the th degree and its properties.. Irrational equations.. Degree c rational indicator.. Exponential function.. 13. Exponent and logarithm To complete the proof of Proposition 12.8, we only need to give one definition and prove one proposition. Definition 13.1. A series a i is said to be absolutely convergent if MINISTRY OF EDUCATION AND SCIENCE OF THE RUSSIAN FEDERATION NOVOSIBIRSK STATE UNIVERSITY SPECIALIZED EDUCATION AND RESEARCH CENTER Mathematics Grade 10 RESEARCH OF FUNCTIONS Novosibirsk For verification LECTURE N. Scalar field. Directional derivative. Gradient. Tangent plane and normal to the surface. Extrema of a function of several variables. Conditional extremum. Scalar field. Derivative with respect to MINISTRY OF EDUCATION AND SCIENCE OF THE RUSSIAN FEDERATION NOVOSIBIRSK STATE UNIVERSITY SPECIALIZED EDUCATION AND RESEARCH CENTER Mathematics grade 0 SEQUENCE LIMITS Novosibirsk Intuitive Definition of the inverse function and its properties: lemma on the mutual monotonicity of the direct and inverse functions; symmetry of graphs of direct and inverse functions; theorems on the existence and continuity of the inverse function for a function that is strictly monotonic on a segment, interval and half-interval. Examples of inverse functions. An example of solving a problem. Proofs of properties and theorems. Definition of an inverse function From the definition it follows that Property of symmetry of graphs of direct and inverse functions Theorem on the existence and continuity of an inverse function on an interval For an increasing function. For decreasing - . Theorem on the existence and continuity of an inverse function on an interval For an increasing function. In a similar way, we can formulate the theorem on the existence and continuity of the inverse function on a half-interval. If the function is continuous and strictly increases (decreases) on the half-interval or , then on the half-interval or the inverse function is defined, which strictly increases (decreases). Here . If strictly increasing, then the intervals and correspond to the intervals and . If strictly decreasing, then the intervals and correspond to the intervals and . Graphs y = sin x and inverse function y = arcsin x.
Let's consider trigonometric function sinus: . It is defined and continuous for all values of the argument, but is not monotonic. However, if you narrow the scope of definition, you can identify monotonous areas. So, on the segment , the function is defined, continuous, strictly increasing and takes values from -1
to +1
. Therefore, it has an inverse function on it, which is called arcsine. The arcsine has a domain and a set of values. Graphs y = 2 x and inverse function y = log 2 x.
The exponential function is defined, continuous and strictly increasing for all values of the argument. Its value set is an open interval. The inverse function is the logarithm to base two. It has a domain of definition and a set of meanings. Graphs y = x 2
and inverse function. Power function defined and continuous for everyone. The set of its values is the half-interval. But it is not monotonic for all values of the argument. However, on the half-interval it is continuous and increases strictly monotonically. Therefore, if we take the set as the domain of definition, then there is an inverse function called square root. An inverse function has a domain and a set of values. Prove that the equation , where n is a natural number, is a real non-negative number, has a unique solution on the set of real numbers, . This solution is called the n root of a. That is, you need to show that any non-negative number has a unique root of degree n. Consider a function of the variable x: Let us prove that it is continuous. Let us prove that function (A1) strictly increases as . Let's find the set of values of the function at . According to the inverse function theorem, the inverse function is defined and continuous on an interval. That is, for anyone there is a unique one that satisfies the equation. Since we have , this means that for any , the equation has a unique solution, which is called a root of degree n of the number x: Let a function have a domain of definition X and a set of values Y. Let us prove that it has an inverse function. Based on , we need to prove that Let's assume the opposite. Let there be numbers, so that . Let it be so. Otherwise, let's change the notation so that it is . Then, due to the strict monotonicity of f, one of the inequalities must be satisfied: Let the function be strictly increasing. Let us prove that the inverse function is also strictly increasing. Let us introduce the following notation: Let's assume the opposite. Let it be, but. If, then. This case disappears. Let . Then, due to the strict increase of the function , , or . A contradiction arose. Therefore, only chance is possible. The lemma is proven for a strictly increasing function. This lemma can be proven in a similar way for a strictly decreasing function. Let be an arbitrary point on the graph of a direct function: Graph of the inverse function y = f -1(x) is symmetrical to the graph of the direct function y = f (x) relative to the straight line y = x. From points A and S we lower perpendiculars to the coordinate axis. Then Through point A we draw a line perpendicular to line . Let the lines intersect at point C. We construct a point S on a straight line so that . Then point S will be symmetrical to point A relative to the straight line. Consider triangles and . They have two sides of equal length: and, and equal angles between them: . Therefore they are congruent. Then Consider a triangle. Since then Now we find and: So, equation (2.2): Since we chose point A arbitrarily, this applies to all points on the graph: The property has been proven. Let denote the domain of definition of the function - the segment. 1. Let us show that the set of function values is the segment: Indeed, since the function is continuous on the segment, then, according to Weierstrass’s theorem, it reaches a minimum and a maximum on it. Then, by the Bolzano-Cauchy theorem, the function takes all values from the segment. That is, for anyone there is , for which . Since there is a minimum and a maximum, the function takes only values from the set on the segment. 2. Since the function is strictly monotonic, then according to the above, there is an inverse function, which is also strictly monotonic (increases if it increases; and decreases if it decreases). The domain of the inverse function is the set, and the set of values is the set. 3. Now we prove that the inverse function is continuous. 3.1. Let there be an arbitrary internal point of the segment: . Let us prove that the inverse function is continuous at this point. Let the point correspond to it. Since the inverse function is strictly monotonic, that is, the interior point of the segment: Note that we can take it as small as we like. Indeed, if we have found a function for which inequalities (3.1) are satisfied for sufficiently small values of , then they will automatically be satisfied for any large values of , if we put at . Let us take it so small that the points and belong to the segment: Let us transform the first inequality (3.1): For any ε > 0
there is δ, so |f -1 (y) - f -1 (y 0) |< ε
for all |y - y 0
| < δ
.
Inequalities (3.3) define an open interval, the ends of which are distant from the point at distances and . Let there be the smallest of these distances: So we found that for small enough , there is , so that 3.2. Now consider the ends of the domain of definition. Here all the reasoning remains the same. You just need to consider one-sided neighborhoods of these points. Instead of a dot there will be or, and instead of a dot - or. So, for an increasing function , . For a decreasing function, . The theorem has been proven. Let denote the domain of definition of the function - an open interval. Let be the set of its values. According to the above, there is an inverse function that has a domain of definition, a set of values and is strictly monotonic (increases if it increases and decreases if it decreases). It remains for us to prove that 1. Let us show that the set of function values is an open interval: Like any non-empty set whose elements have a comparison operation, the set of function values has lower and upper bounds: 1.1. Let us show that the points and do not belong to the set of function values. That is, a set of values cannot be a segment. If or is point at infinity: or , then such a point is not an element of the set. Therefore, it cannot belong to multiple values. Let (or ) be a finite number. Let's assume the opposite. Let the point (or ) belong to the set of function values. That is, there is such for which (or). Let us take points and satisfying the inequalities: 1.2.
Now we will show that the set of values is an interval
,
and not by combining intervals and points. That is, for any point
exists
,
for which
.
According to the definitions of lower and upper bounds, in any neighborhood of points
And
contains at least one element of the set
.
Let
- an arbitrary number belonging to the interval
:
.
Then for the neighborhood
exists
,
for which Because
And
,
That
.
Then So we have a segment
,
Where
If
increases; Because
,
then we have thereby shown that for any
exists
,
for which
.
This means that the set of function values
is an open interval
.
2.
Now we will show that the inverse function is continuous at an arbitrary point
interval
:
.
To do this, apply to the segment
.
Because
,
then the inverse function
continuous on the segment
,
including at the point
.
The theorem has been proven. Used literature: Much has already passed and now you are a graduate, if, of course, you write your thesis on time. But life is such a thing that only now it becomes clear to you that, having ceased to be a student, you will lose all the student joys, many of which you have never tried, putting everything off and putting it off until later. And now, instead of catching up, you're working on your thesis? There is an excellent solution: download the thesis you need from our website - and you will instantly have a lot of free time! The course project is the first serious practical work. It is with the writing of coursework that preparation for the development of diploma projects begins. If a student learns to correctly present the content of a topic in a course project and format it competently, then in the future he will not have problems either with writing reports or with compiling theses, nor with performing other practical tasks. In order to assist students in writing this type of student work and to clarify questions that arise during its preparation, in fact, this information section was created. Currently in higher educational institutions In Kazakhstan and the CIS countries, the level of higher education is very common vocational education, which follows a bachelor's degree - a master's degree. In the master's program, students study with the aim of obtaining a master's degree, which is recognized in most countries of the world more than a bachelor's degree, and is also recognized by foreign employers. The result of master's studies is the defense of a master's thesis. After completing any type of student internship (educational, industrial, pre-graduation), a report is required. This document will be confirmation practical work student and the basis for forming an assessment for practice. Usually, in order to draw up a report on the internship, you need to collect and analyze information about the enterprise, consider the structure and work routine of the organization in which the internship is taking place, draw up a calendar plan and describe your practical activities. Lesson objectives: Educational: Developmental: Educational: to develop communicative competence. Equipment: computer, projector, screen, interactive whiteboard SMART Board, handouts ( independent work) for group work. 1. Organizational moment. Target – preparing students for work in class: Definition of absentees, Getting students in the mood for work, organizing attention; State the topic and purpose of the lesson. 2. Updating students’ basic knowledge. Frontal survey. Target - establish the correctness and awareness of the studied theoretical material, repetition of the material covered.<Приложение
1 >
A graph of a function is shown on the interactive whiteboard for students. The teacher formulates a task - consider the graph of a function and list the studied properties of the function. Students list the properties of a function in accordance with the research design. The teacher, to the right of the graph of the function, writes down the named properties with a marker on the interactive board. Function properties: At the end of the study, the teacher reports that today in the lesson they will become acquainted with another property of a function - reversibility. To meaningfully study new material, the teacher invites the children to get acquainted with the main questions that students must answer at the end of the lesson. The questions are written on a regular board and each student has them as handouts (distributed before the lesson) 3. Explanation of new material. Target - generate knowledge on a new topic in accordance with the program material; study the property of reversibility of a function and teach how to find the inverse function of a given one;
develop substantive speech. The teacher presents the material in accordance with the material in the paragraph. On the interactive whiteboard, the teacher compares the graphs of two functions whose domains of definition and sets of values are the same, but one of the functions is monotonic and the other is not, thereby introducing students to the concept of an invertible function. The teacher then formulates the definition of an invertible function and conducts a proof of the invertible function theorem using the graph of a monotonic function on the interactive whiteboard. Definition 1: The function y=f(x), x X is called reversible, if it takes any of its values only at one point of the set X. Theorem: If a function y=f(x) is monotonic on a set X, then it is invertible. Proof: (As the proof of the theorem progresses, the teacher uses a marker to make all the necessary explanations on the drawing) Before formulating the definition of an inverse function, the teacher asks students to determine which of the proposed functions is invertible? The interactive whiteboard shows graphs of functions and writes several analytically defined functions: B) G) y = 2x + 5 D) y = -x 2 + 7 The teacher introduces the definition of an inverse function. Definition 2: Let the invertible function y=f(x) defined on the set X And E(f)=Y. Let's match each one y from Y that's the only meaning X, at which f(x)=y. Then we get a function that is defined on Y, A X– function range This function is designated x=f -1 (y) and is called the inverse of the function y=f(x). Students are asked to draw a conclusion about the connection between the domain of definition and the set of values of inverse functions. To consider the question of how to find the inverse of a given function, the teacher attracted two students. The day before, the children received an assignment from the teacher to independently analyze the analytical and graphical methods of finding the inverse function of a given function. The teacher acted as a consultant in preparing students for the lesson. Message from the first student. Note: the monotonicity of the function is sufficient condition for the existence of the inverse function. But it is not a necessary condition. The student gave examples of various situations when a function is not monotonic but invertible, when a function is not monotonic and not invertible, when it is monotonic and invertible The student then introduces students to a method for finding the inverse function given analytically. Finding algorithm Then he solves two examples to find the inverse function of a given one. Example 1: Show that for the function y=5x-3 there is an inverse function and find its analytical expression. Solution. The linear function y=5x-3 is defined on R, increases on R, and its range of values is R. This means that the inverse function exists on R. To find its analytical expression, solve the equation y=5x-3 for x; we get This is the required inverse function. It is defined and increasing on R. Example 2: Show that for the function y=x 2, x≤0 there is an inverse function, and find its analytical expression. The function is continuous, monotonic in its domain of definition, therefore, it is invertible. Having analyzed the domains of definition and sets of values of the function, a corresponding conclusion is made about the analytical expression for the inverse function. The second student makes a presentation about graphic method of finding the inverse function. During his explanation, the student uses the capabilities of the interactive whiteboard. To obtain a graph of the function y=f -1 (x), inverse to the function y=f(x), it is necessary to transform the graph of the function y=f(x) symmetrically with respect to the straight line y=x. During the explanation on the interactive whiteboard, the following task is performed: Construct a graph of a function and a graph of its inverse function in the same coordinate system. Write down the analytical expression for the inverse function. 4. Primary consolidation of new material. Target - establish the correctness and awareness of the understanding of the studied material, identify gaps in the primary understanding of the material, and correct them. Students are divided into pairs. They are given sheets of tasks, in which they do the work in pairs. The time to complete the work is limited (5-7 minutes). One pair of students works on the computer, the projector turns off during this time and the rest of the children cannot see how the students work on the computer. At the end of the time (it is assumed that the majority of students have completed the work), the students’ work is shown on the interactive board (the projector is turned on again), where it is determined during the check whether the task was completed correctly in pairs. If necessary, the teacher carries out correctional and explanatory work. Independent work in pairs<Appendix 2 > 5. Lesson summary. Regarding the questions that were asked before the lecture. Announcement of grades for the lesson. Homework §10. No. 10.6(a,c) 10.8-10.9(b) 10.12 (b) Algebra and the beginnings of analysis. Grade 10 In 2 parts for general education institutions (profile level) / A.G. Mordkovich, L.O. Denishcheva, T.A. Koreshkova, etc.; edited by A.G. Mordkovich, M: Mnemosyne, 2007
Definition and properties
Let a function have a domain of definition X and a set of values Y. And let it have the property:
for everyone.
Then for any element from the set Y one can associate only one element of the set X for which . This correspondence defines a function called inverse function To . The inverse function is denoted as follows:
.
;
for everyone;
for everyone.
The graphs of direct and inverse functions are symmetrical with respect to the straight line.
Let the function be continuous and strictly increasing (decreasing) on the segment. Then the inverse function is defined and continuous on the segment, which strictly increases (decreases).
Let the function be continuous and strictly increasing (decreasing) on an open finite or infinite interval. Then the inverse function is defined and continuous on the interval, which strictly increases (decreases).
For decreasing: .
This theorem is proven in the same way as the theorem on the existence and continuity of an inverse function on an interval.Examples of inverse functions
arcsine
Logarithm
Square root
Example. Proof of the existence and uniqueness of a root of degree n
(P1) .
Using the definition of continuity, we show that
.
We apply Newton's binomial formula:
(P2)
.
Let's apply the arithmetic properties of function limits. Since , then only the first term is nonzero:
.
Continuity has been proven.
Let's take arbitrary numbers connected by inequalities:
,
,
.
We need to show that . Let's introduce variables. Then . Since , then from (A2) it is clear that . Or
.
Strict increase has been proven.
At point , .
Let's find the limit.
To do this, we apply Bernoulli's inequality. When we have:
.
Since , then and .
Applying the property of inequalities for infinitely large functions, we find that .
Thus, , .
.
Proofs of properties and theorems
Proof of the lemma on the mutual monotonicity of the direct and inverse functions
for everyone.
if f is strictly increasing;
if f is strictly decreasing.
That is . A contradiction arose. Therefore, it has an inverse function.
. That is, we need to prove that if , then .Proof of the property about the symmetry of the graphs of direct and inverse functions
(2.1)
.
Let us show that a point symmetrical to point A relative to a straight line belongs to the graph of the inverse function:
.
From the definition of the inverse function it follows that
(2.2)
.
Thus, we need to show (2.2).
,
.
.
.
The same applies to the triangle:
.
Then
.
;
.
(2.2)
is satisfied, since , and (2.1) is satisfied:
(2.1)
.
all points on the graph of a function, symmetrically reflected with respect to the straight line, belong to the graph of the inverse function.
Next we can change places. As a result we get that
all points of the graph of a function, symmetrically reflected with respect to a straight line, belong to the graph of the function.
It follows that the graphs of functions and are symmetrical with respect to the straight line.Proof of the theorem on the existence and continuity of the inverse function on an interval
,
Where .
.
According to the definition of continuity, we need to prove that for any there is a function such that
(3.1)
for everyone.
.
Let us introduce and arrange the notation:
.
(3.1)
for everyone.
;
;
;
(3.2)
.
Since it is strictly monotonic, it follows that
(3.3.1)
, if it increases;
(3.3.2)
, if it decreases.
Since the inverse function is also strictly monotonic, inequalities (3.3) imply inequalities (3.2).
.
Due to the strict monotonicity of , , . Therefore and. Then the interval will lie in the interval defined by inequalities (3.3). And for all values belonging to it, inequalities (3.2) will be satisfied.
at .
Now let's change the notation.
For small enough, there is such a thing, so
at .
This means that the inverse function is continuous throughout internal points.
at .
The inverse function is continuous at the point, since for any sufficiently small there is , so that
at .
The inverse function is continuous at the point, since for any sufficiently small there is , so that
at .
The inverse function is continuous at the point, since for any sufficiently small there is , so that
at .Proof of the theorem on the existence and continuity of the inverse function on an interval
1) the set is an open interval, and that
2) the inverse function is continuous on it.
Here .
.
.
Here and can be finite numbers or symbols and .
.
Since the function is strictly monotonic, then
, if f increases;
, if f is decreasing.
That is, we have found a point at which the function value is less (more
). But this contradicts the definition of the lower (upper) bound, according to which
for everyone
.
Therefore the points
And
cannot belong to multiple values
functions
.
.
For the surrounding area
exists
,
for which
.
(4.1.1)
If
increases;
(4.1.2)
If
decreases.
Inequalities (4.1) are easy to prove by contradiction. But you can use, according to which on the set
there is an inverse function
,
which strictly increases if increases
and strictly decreases if decreases
.
Then we immediately obtain inequalities (4.1).
If
decreases.
At the ends of the segment the function takes values
And
.
Because
,
then by the Bolzano-Cauchy theorem, there is a point
,
for which
.
O.I. Besov. Lectures on mathematical analysis. Part 1. Moscow, 2004.
CM. Nikolsky. Course of mathematical analysis. Volume 1. Moscow, 1983.Finished works
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Then from the fact that x 1<
x 2 it follows that f(x 1) < f(x 2).
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